a) \(2.57 : x = 28.27 : 15.4\)
\(2.57 \cdot 15.4 = 28.27 \cdot x\)
\(39.578 = 28.27x\)
\(x = \frac{39.578}{28.27}\)
\(x = 1.4\)
б) \(42.6 : 20.59 = y : 7.83\)
\(42.6 \cdot 7.83 = 20.59 \cdot y\)
\(333.558 = 20.59y\)
\(y = \frac{333.558}{20.59}\)
\(y = 16.2\)
в) \(a : 5.2 = 22.1 : 1.69\)
\(a \cdot 1.69 = 5.2 \cdot 22.1\)
\(1.69a = 114.92\)
\(a = \frac{114.92}{1.69}\)
\(a = 68\)
г) \(\frac{13.4}{16.75} = \frac{32}{b}\)
\(13.4 \cdot b = 16.75 \cdot 32\)
\(13.4b = 536\)
\(b = \frac{536}{13.4}\)
\(b = 40\)
д) \(\frac{3}{5} : 1.5 = x : \frac{18}{5}\)
\(\frac{3}{5} : \frac{3}{2} = x : \frac{18}{5}\)
\(\frac{3}{5} \cdot \frac{18}{5} = \frac{3}{2} \cdot x\)
\(\frac{54}{25} = \frac{3}{2}x\)
\(x = \frac{54}{25} \cdot \frac{2}{3}\)
\(x = \frac{36}{25}\) или \(x = 1.44\)
е) \(\frac{2x}{3.3} = \frac{4}{11}\)
\(2x \cdot 11 = 3.3 \cdot 4\)
\(22x = 13.2\)
\(x = \frac{13.2}{22}\)
\(x = 0.6\)
ж) \(15 : (x - 5) = 7.5 : 2\frac{1}{2}\)
\(15 : (x - 5) = 7.5 : 2.5\)
\(15 \cdot 2.5 = 7.5 \cdot (x - 5)\)
\(37.5 = 7.5x - 37.5\)
\(75 = 7.5x\)
\(x = \frac{75}{7.5}\)
\(x = 10\)
з) \(5\frac{3}{5} : 7\frac{2}{3} = 4\frac{1}{2} : (y + 2.3)\)
\(\frac{28}{5} : \frac{23}{3} = \frac{9}{2} : (y + 2.3)\)
\(\frac{28}{5} \cdot (y + 2.3) = \frac{23}{3} \cdot \frac{9}{2}\)
\(\frac{28}{5}y + \frac{28}{5} \cdot 2.3 = \frac{69}{2}\)
\(5.6y + 12.88 = 34.5\)
\(5.6y = 21.62\)
\(y = \frac{21.62}{5.6}\)
\(y = 3.8607\) (приблизительно)
Ответ: a) x = 1.4; б) y = 16.2; в) a = 68; г) b = 40; д) x = 1.44; е) x = 0.6; ж) x = 10; з) y = 3.86 (округлено до сотых)