№ 2: (1) log₃ 54 − log₃ 2 + log₇ 49; (2) log₁₁ ³√121; (3) 3^(2 log₃ 5); (4) log₂ 1; (5) log₂ 2.

1) log₃ 54 − log₃ 2 = log₃ 27 = 3; log₇ 49 = 2. Сумма: 3 + 2 = 5.

2) ³√121 = 11^(2/3), поэтому log₁₁ ³√121 = 2/3.

3) 3^(2 log₃ 5) = 3^(log₃ 25) = 25.

4) log₂ 1 = 0.

5) log₂ 2 = 1.