№ 3: (1) log₃ 162 − log₃ 2 + log₅ 5; (2) log₁₂ ³√144; (3) 3^(2 log₃ 2); (4) log₅ 1; (5) log₄ 4.

1) log₃(162 ÷ 2) + log₅ 5 = log₃ 81 + 1 = 4 + 1 = 5.

2) ³√144 = 12^(2/3), поэтому log₁₂ ³√144 = 2/3.

3) 3^(2 log₃ 2) = 3^(log₃ 4) = 4.

4) log₅ 1 = 0.

5) log₄ 4 = 1.