Решение:
- \(\sqrt[3]{x} - 6 = -3\)
\(\sqrt[3]{x} = -3 + 6\)
\(\sqrt[3]{x} = 3\)
\(x = 3^3\)
\(x = 27\) - \(2 \sin x = -1\)
\(\sin x = -\frac{1}{2}\)
\(x = \pm \frac{\pi}{6} + 2\pi k, k \in \mathbb{Z}\)
Ответ: 1) 27; 2) \(x = \pm \frac{\pi}{6} + 2\pi k, k \in \mathbb{Z}\).