Ответ:\(\sin(90^\circ+30^\circ)=\sin120^\circ=\sin60^\circ=\frac{\sqrt3}{2}\).\(\cos(90^\circ+30^\circ)=\cos120^\circ=-\cos60^\circ=-\frac12\).Ответ: 1) \(\frac{\sqrt3}{2}\); 2) \(-\frac12\).