a) \(\frac{1}{2} + \frac{1}{3}\), г) \(\frac{3}{4} + \frac{2}{5}\), ж) \(\frac{1}{8} + \frac{1}{4}\), н) \(\frac{5}{9} + \frac{3}{4}\) b) \(\frac{1}{4} + \frac{2}{5}\), д) \(\frac{5}{7} - \frac{1}{6}\), з) \(\frac{2}{3} - \frac{5}{9}\), о) \(\frac{23}{40} - \frac{3}{8}\) в) \(\frac{2}{3} + \frac{1}{4}\), e) \(\frac{3}{4} - \frac{1}{3}\), и) \(\frac{1}{2} - \frac{5}{12}\), п) \(\frac{9}{35} - \frac{3}{28}\)

Решим примеры на сложение и вычитание дробей.

a) \(\frac{1}{2} + \frac{1}{3}\) = \(\frac{3}{6} + \frac{2}{6}\) = \(\frac{5}{6}\)

б) \(\frac{1}{4} + \frac{2}{5}\) = \(\frac{5}{20} + \frac{8}{20}\) = \(\frac{13}{20}\)

в) \(\frac{2}{3} + \frac{1}{4}\) = \(\frac{8}{12} + \frac{3}{12}\) = \(\frac{11}{12}\)

г) \(\frac{3}{4} + \frac{2}{5}\) = \(\frac{15}{20} + \frac{8}{20}\) = \(\frac{23}{20}\) = 1\(\frac{3}{20}\)

д) \(\frac{5}{7} - \frac{1}{6}\) = \(\frac{30}{42} - \frac{7}{42}\) = \(\frac{23}{42}\)

e) \(\frac{3}{4} - \frac{1}{3}\) = \(\frac{9}{12} - \frac{4}{12}\) = \(\frac{5}{12}\)

ж) \(\frac{1}{8} + \frac{1}{4}\) = \(\frac{1}{8} + \frac{2}{8}\) = \(\frac{3}{8}\)

з) \(\frac{2}{3} - \frac{5}{9}\) = \(\frac{6}{9} - \frac{5}{9}\) = \(\frac{1}{9}\)

и) \(\frac{1}{2} - \frac{5}{12}\) = \(\frac{6}{12} - \frac{5}{12}\) = \(\frac{1}{12}\)

н) \(\frac{5}{9} + \frac{3}{4}\) = \(\frac{20}{36} + \frac{27}{36}\) = \(\frac{47}{36}\) = 1\(\frac{11}{36}\)

о) \(\frac{23}{40} - \frac{3}{8}\) = \(\frac{23}{40} - \frac{15}{40}\) = \(\frac{8}{40}\) = \(\frac{1}{5}\)

п) \(\frac{9}{35} - \frac{3}{28}\) = \(\frac{36}{140} - \frac{15}{140}\) = \(\frac{21}{140}\) = \(\frac{3}{20}\)

Ответ: a) \(\frac{5}{6}\); б) \(\frac{13}{20}\); в) \(\frac{11}{12}\); г) 1\(\frac{3}{20}\); д) \(\frac{23}{42}\); e) \(\frac{5}{12}\); ж) \(\frac{3}{8}\); з) \(\frac{1}{9}\); и) \(\frac{1}{12}\); н) 1\(\frac{11}{36}\); о) \(\frac{1}{5}\); п) \(\frac{3}{20}\)