Вопрос:

378. Найдите значение выражения: a) \(\frac{1}{4}\) – (1 – \(\frac{11}{12}\)); б) 2 – (\(\frac{13}{33}\) – \(\frac{5}{22}\)); в) 6\(\frac{3}{16}\) – (2\(\frac{3}{8}\) + 3\(\frac{5}{12}\)); г) 8\(\frac{1}{12}\) – 3\(\frac{4}{15}\) – 1\(\frac{7}{30}\); д) (13 – 8\(\frac{5}{12}\)) + (17\(\frac{1}{2}\) – 16\(\frac{1}{5}\)); е) (63\(\frac{2}{3}\) + 3\(\frac{1}{8}\)) – (13 – 10\(\frac{5}{9}\));

Смотреть решения всех заданий с листа

Ответ:

Найдем значение выражения.

a) \(\frac{1}{4} - (1 - \frac{11}{12}) = \frac{1}{4} - (\frac{12}{12} - \frac{11}{12}) = \frac{1}{4} - \frac{1}{12} = \frac{3}{12} - \frac{1}{12} = \frac{2}{12} = \frac{1}{6}\)

б) \(2 - (\frac{13}{33} - \frac{5}{22}) = 2 - (\frac{26}{66} - \frac{15}{66}) = 2 - \frac{11}{66} = 2 - \frac{1}{6} = \frac{12}{6} - \frac{1}{6} = \frac{11}{6} = 1\frac{5}{6}\)

в) \(6\frac{3}{16} - (2\frac{3}{8} + 3\frac{5}{12}) = 6\frac{3}{16} - (2\frac{9}{24} + 3\frac{10}{24}) = 6\frac{3}{16} - 5\frac{19}{24} = 6\frac{9}{48} - 5\frac{38}{48} = 5\frac{57}{48} - 5\frac{38}{48} = \frac{19}{48}\)

г) \(8\frac{1}{12} - 3\frac{4}{15} - 1\frac{7}{30} = 8\frac{5}{60} - 3\frac{16}{60} - 1\frac{14}{60} = 7\frac{65}{60} - 3\frac{16}{60} - 1\frac{14}{60} = 4\frac{49}{60} - 1\frac{14}{60} = 3\frac{35}{60} = 3\frac{7}{12}\)

д) \((13 - 8\frac{5}{12}) + (17\frac{1}{2} - 16\frac{1}{5}) = (12\frac{12}{12} - 8\frac{5}{12}) + (17\frac{5}{10} - 16\frac{2}{10}) = 4\frac{7}{12} + 1\frac{3}{10} = 4\frac{35}{60} + 1\frac{18}{60} = 5\frac{53}{60}\)

е) \((63\frac{2}{3} + 3\frac{1}{8}) - (13 - 10\frac{5}{9}) = (63\frac{16}{24} + 3\frac{3}{24}) - (12\frac{9}{9} - 10\frac{5}{9}) = 66\frac{19}{24} - 2\frac{4}{9} = 66\frac{57}{72} - 2\frac{32}{72} = 64\frac{25}{72}\)

Ответ: a) \(\frac{1}{6}\); б) \(1\frac{5}{6}\); в) \(\frac{19}{48}\); г) \(3\frac{7}{12}\); д) \(5\frac{53}{60}\); е) \(64\frac{25}{72}\)

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