и) 1\(\frac{5}{12}\) – \(\frac{9}{10}\); к) 6\(\frac{3}{10}\) – \(\frac{11}{15}\); л) 5\(\frac{7}{8}\) – \(\frac{9}{10}\); м) 7\(\frac{5}{12}\) – 3\(\frac{2}{9}\); н) 10\(\frac{1}{2}\) – 4\(\frac{9}{14}\); о) 7\(\frac{4}{7}\) – 5\(\frac{7}{9}\); п) 2\(\frac{3}{10}\) – 1\(\frac{11}{15}\); р) 5\(\frac{3}{8}\) – 3\(\frac{5}{6}\);

Выполним вычитание.

и) \(1\frac{5}{12} - \frac{9}{10} = 1\frac{25}{60} - \frac{54}{60} = \frac{85}{60} - \frac{54}{60} = \frac{31}{60}\)

к) \(6\frac{3}{10} - \frac{11}{15} = 6\frac{9}{30} - \frac{22}{30} = 5\frac{39}{30} - \frac{22}{30} = 5\frac{17}{30}\)

л) \(5\frac{7}{8} - \frac{9}{10} = 5\frac{35}{40} - \frac{36}{40} = 4\frac{75}{40} - \frac{36}{40} = 4\frac{39}{40}\)

м) \(7\frac{5}{12} - 3\frac{2}{9} = 7\frac{15}{36} - 3\frac{8}{36} = 4\frac{7}{36}\)

н) \(10\frac{1}{2} - 4\frac{9}{14} = 10\frac{7}{14} - 4\frac{9}{14} = 9\frac{21}{14} - 4\frac{9}{14} = 5\frac{12}{14} = 5\frac{6}{7}\)

о) \(7\frac{4}{7} - 5\frac{7}{9} = 7\frac{36}{63} - 5\frac{49}{63} = 6\frac{99}{63} - 5\frac{49}{63} = 1\frac{50}{63}\)

п) \(2\frac{3}{10} - 1\frac{11}{15} = 2\frac{9}{30} - 1\frac{22}{30} = 1\frac{39}{30} - 1\frac{22}{30} = \frac{17}{30}\)

р) \(5\frac{3}{8} - 3\frac{5}{6} = 5\frac{9}{24} - 3\frac{20}{24} = 4\frac{33}{24} - 3\frac{20}{24} = 1\frac{13}{24}\)

Ответ: и) \(\frac{31}{60}\); к) \(5\frac{17}{30}\); л) \(4\frac{39}{40}\); м) \(4\frac{7}{36}\); н) \(5\frac{6}{7}\); о) \(1\frac{50}{63}\); п) \(\frac{17}{30}\); р) \(1\frac{13}{24}\)