б) \(16\frac{5}{6}y + y - \frac{3}{8}y\) при \(y = 1\frac{1}{15}\);

б) Упростим и найдем значение выражения:$$\begin{aligned}16\frac{5}{6}y + y - \frac{3}{8}y &= y(16\frac{5}{6} + 1 - \frac{3}{8}) = y(16 + \frac{5}{6} + 1 - \frac{3}{8}) = y(17 + \frac{5}{6} - \frac{3}{8}) =\\ &= y(17 + \frac{5 \cdot 4}{6 \cdot 4} - \frac{3 \cdot 3}{8 \cdot 3}) = y(17 + \frac{20}{24} - \frac{9}{24}) = y(17 + \frac{20 - 9}{24}) = y(17 + \frac{11}{24}) =\\ &= 17\frac{11}{24}y.\\\text{При }y &= 1\frac{1}{15} = \frac{1 \cdot 15 + 1}{15} = \frac{15 + 1}{15} = \frac{16}{15},\\\\17\frac{11}{24}y &= \frac{17 \cdot 24 + 11}{24} \cdot \frac{16}{15} = \frac{408 + 11}{24} \cdot \frac{16}{15} = \frac{419}{24} \cdot \frac{16}{15} = \frac{419}{3} \cdot \frac{2}{15} = \frac{419 \cdot 2}{3 \cdot 15} = \frac{838}{45} = 18\frac{28}{45}.\end{aligned}$$

Ответ: \(18\frac{28}{45}\)