$$lim_{x \to -6} \frac{x+6}{x^2-36}$$
$$lim_{x \to -6} \frac{x+6}{(x-6)(x+6)} = lim_{x \to -6} \frac{1}{x-6} = \frac{1}{-6-6} = \frac{1}{-12} = -\frac{1}{12}$$
Ответ: -1/12