r) log₂² x + 7 log₂ x + 49 = -218/log₂ x.

log₂² x + 7 log₂ x + 49 = -218/log₂ x

Пусть t = log₂ x, тогда:

t² + 7t + 49 = -218/t

t³ + 7t² + 49t = -218

t³ + 7t² + 49t + 218 = 0

t = -5.214

log₂ x = -5.214

x = 2⁻⁵°²¹⁴

x ≈ 0.027

Ответ: ≈ 0.027