π1\n6) sin cos+;\n884\nπ\nπ

$$sin\frac{\pi}{8}cos\frac{\pi}{8}+\frac{1}{4}=\frac{1}{2}\cdot2sin\frac{\pi}{8}cos\frac{\pi}{8}+\frac{1}{4}=\frac{1}{2}sin(2\cdot\frac{\pi}{8})+\frac{1}{4}=\frac{1}{2}sin\frac{\pi}{4}+\frac{1}{4}=\frac{1}{2}\cdot\frac{\sqrt{2}}{2}+\frac{1}{4}=\frac{\sqrt{2}}{4}+\frac{1}{4}=\frac{\sqrt{2}+1}{4}$$.

Ответ:$$\frac{\sqrt{2}+1}{4}$$