\(1 \frac{3}{5} = \frac{1 \cdot 5 + 3}{5} = \frac{8}{5}\)
\(\frac{8}{5} + \frac{3}{4} + \frac{3}{8}\)
\(\frac{8 \cdot 8}{5 \cdot 8} + \frac{3 \cdot 10}{4 \cdot 10} + \frac{3 \cdot 5}{8 \cdot 5} = \frac{64}{40} + \frac{30}{40} + \frac{15}{40}\)
\(\frac{64 + 30 + 15}{40} = \frac{109}{40}\)
\(\frac{109}{40} = 2 \frac{29}{40}\)
Ответ: 2 29/40