Ответ:
\[\sin A=\sqrt{1-\left(\frac9{41}\right)^2}=\sqrt{\frac{1600}{1681}}=\frac{40}{41}.\]
\[\operatorname{tg}A=\frac{40/41}{9/41}=\frac{40}{9}.\]
Ответ: \(\operatorname{tg}A=\frac{40}{9}\).
\[\sin A=\sqrt{1-\left(\frac9{41}\right)^2}=\sqrt{\frac{1600}{1681}}=\frac{40}{41}.\]
\[\operatorname{tg}A=\frac{40/41}{9/41}=\frac{40}{9}.\]
Ответ: \(\operatorname{tg}A=\frac{40}{9}\).