Решение:
\(x^6y + xy^6 = xy(x^5 + y^5)\)
\(2(2x - 3y) = -2(3y - 2x)\)
\[ \frac{xy(x^5 + y^5)}{5(3y - 2x)} \cdot \frac{-2(3y - 2x)}{x^5 + y^5} \]
\[ \frac{xy \cdot (-2)}{5} = -\frac{2xy}{5} \]
\[ -\frac{2 \cdot \frac{1}{8} \cdot (-8)}{5} = -\frac{2 \cdot (-1)}{5} = -\frac{-2}{5} = \frac{2}{5} \]
Ответ: 2/5