\[ \frac{x-3}{2} = \frac{1-4x}{3} \]
\[ 6 \cdot \frac{x-3}{2} = 6 \cdot \frac{1-4x}{3} \]
\[ 3(x-3) = 2(1-4x) \]
\[ 3x - 9 = 2 - 8x \]
\[ 3x + 8x = 2 + 9 \]
\[ 11x = 11 \]
\[ x = \frac{11}{11} \]
\[ x = 1 \]
Ответ: x = 1.