\[ (a+2)^2 - a(4-7a) = (a^2 + 4a + 4) - (4a - 7a^2) \]
\[ = a^2 + 4a + 4 - 4a + 7a^2 \]
\[ = (a^2 + 7a^2) + (4a - 4a) + 4 \]
\[ = 8a^2 + 4 \]
\[ 8 \left(-\frac{1}{2}\right)^2 + 4 = 8 \left(\frac{1}{4}\right) + 4 = 2 + 4 = 6 \]
Ответ: 6