8. log₁₆ 2 · log₂ 32 + log₇ 1

\(\log_{16}2=\frac{1}{4}\), \(\log_2 32=5\), \(\log_7 1=0\).

\(\frac{1}{4}\cdot 5+0=\frac{5}{4}\).

Ответ: \(\frac{5}{4}\).