Преобразуем смешанные числа в неправильные дроби:
2$$\frac{2}{15}$$ = $$\frac{15 \cdot 2 + 2}{15}$$ = $$\frac{32}{15}$$
1$$\frac{2}{5}$$ = $$\frac{5 \cdot 1 + 2}{5}$$ = $$\frac{7}{5}$$
6$$\frac{1}{4}$$ = $$\frac{4 \cdot 6 + 1}{4}$$ = $$\frac{25}{4}$$
Тогда:
($$\frac{32}{15}$$ - $$\frac{7}{5}$$) · $$\frac{25}{4}$$ = ($$\frac{32}{15}$$ - $$\frac{7 \cdot 3}{5 \cdot 3}$$) · $$\frac{25}{4}$$ = ($$\frac{32}{15}$$ - $$\frac{21}{15}$$) · $$\frac{25}{4}$$ = $$\frac{32-21}{15}$$ · $$\frac{25}{4}$$ = $$\frac{11}{15}$$ · $$\frac{25}{4}$$ = $$\frac{11 \cdot 25}{15 \cdot 4}$$ = $$\frac{11 \cdot 5}{3 \cdot 4}$$ = $$\frac{55}{12}$$ = 4$$\frac{7}{12}$$
Ответ: 4$$\frac{7}{12}$$