г) (\frac{1}{3} + \frac{1}{4}) : (2 - \frac{5}{6}).

1) \frac{1}{3} + \frac{1}{4} = \frac{1 \cdot 4}{3 \cdot 4} + \frac{1 \cdot 3}{4 \cdot 3} = \frac{4}{12} + \frac{3}{12} = \frac{7}{12}

2) 2 - \frac{5}{6} = \frac{2 \cdot 6}{6} - \frac{5}{6} = \frac{12}{6} - \frac{5}{6} = \frac{7}{6}

3) \frac{7}{12} : \frac{7}{6} = \frac{7}{12} \cdot \frac{6}{7} = \frac{7 \cdot 6}{12 \cdot 7} = \frac{42}{84} = \frac{1}{2}

Ответ: \frac{1}{2}