294 3) log5 36-log512 ; log 5 9

$$\frac{log_5 36 - log_5 12}{log_5 9} = \frac{log_5(\frac{36}{12})}{log_5 9} = \frac{log_5 3}{log_5 3^2} = \frac{log_5 3}{2log_5 3} = \frac{1}{2}$$.

Ответ: 1/2