3. Найдите корень уравнения: 3)$$\frac{1}{4}$$x+$$\frac{6}{8}$$+$$\frac{1}{8}$$x=$$\frac{39}{56}$$

3) Найдем корень уравнения $$\frac{1}{4}$$x+$$\frac{6}{8}$$+$$\frac{1}{8}$$x=$$\frac{39}{56}$$

$$\frac{1}{4}$$x+$$\frac{6}{8}$$+$$\frac{1}{8}$$x=$$\frac{39}{56}$$

$$\frac{1}{4}$$x+$$\frac{1}{8}$$x = $$\frac{39}{56}$$-$$\frac{6}{8}$$

$$\frac{2}{8}$$x+$$\frac{1}{8}$$x = $$\frac{39}{56}$$-$$\frac{42}{56}$$

$$\frac{3}{8}$$x = -$$\frac{3}{56}$$

x = -$$\frac{3}{56}$$ : $$\frac{3}{8}$$

x = -$$\frac{3}{56}$$ * $$\frac{8}{3}$$

x = -$$\frac{3*8}{56*3}$$

x = -$$\frac{1}{7}$$

Ответ: -$$\frac{1}{7}$$