Решим через дискриминант: $$D = b^2 - 4ac = (-7)^2 - 4(5)(2) = 49 - 40 = 9$$
$$x_1 = \frac{-b + \sqrt{D}}{2a} = \frac{7 + \sqrt{9}}{2(5)} = \frac{7 + 3}{10} = \frac{10}{10} = 1$$
$$x_2 = \frac{-b - \sqrt{D}}{2a} = \frac{7 - \sqrt{9}}{2(5)} = \frac{7 - 3}{10} = \frac{4}{10} = \frac{2}{5}$$
Ответ: $$x_1 = 1$$, $$x_2 = \frac{2}{5}$$