Решим через дискриминант: $$D = b^2 - 4ac = (-3)^2 - 4(5)(-2) = 9 + 40 = 49$$
$$x_1 = \frac{-b + \sqrt{D}}{2a} = \frac{3 + \sqrt{49}}{2(5)} = \frac{3 + 7}{10} = \frac{10}{10} = 1$$
$$x_2 = \frac{-b - \sqrt{D}}{2a} = \frac{3 - \sqrt{49}}{2(5)} = \frac{3 - 7}{10} = \frac{-4}{10} = -\frac{2}{5}$$
Ответ: $$x_1 = 1$$, $$x_2 = -\frac{2}{5}$$