Уменьшим каждое число на 3:
\(5\frac{4}{5} - 3 = 2\frac{4}{5} = \frac{2 \cdot 5 + 4}{5} = \frac{14}{5}\)
\(7\frac{1}{9} - 3 = 4\frac{1}{9} = \frac{4 \cdot 9 + 1}{9} = \frac{37}{9}\)
\(\frac{9}{19} - 3 = \frac{9}{19} - \frac{3 \cdot 19}{19} = \frac{9 - 57}{19} = \frac{-48}{19}\)
Ответ: \(\frac{14}{5}\), \(\frac{37}{9}\), \(\frac{-48}{19}\)