Вопрос:

5.445 Вычислите: a) \(\frac{1}{2} + \frac{1}{3}\); г) \(\frac{3}{7} + \frac{4}{9}\); ж) \(\frac{1}{6} + \frac{1}{3}\); к) \(\frac{7}{15} - \frac{3}{10}\); н) \(\frac{5}{11} + \frac{3}{5}\); б) \(\frac{1}{3} + \frac{2}{7}\); д) \(\frac{5}{9} - \frac{1}{6}\); з) \(\frac{9}{5} - \frac{7}{10}\); л) \(\frac{3}{8} + \frac{5}{12}\); о) \(\frac{17}{30} - \frac{3}{6}\); в) \(\frac{2}{5} + \frac{1}{3}\); е) \(\frac{3}{4} - \frac{1}{3}\); и) \(\frac{1}{2} - \(\frac{3}{8}\); м) \(\frac{5}{9} - \frac{1}{6}\); п) \(\frac{17}{35} - \frac{4}{15}\)

Ответ:

a) \(\frac{1}{2} + \frac{1}{3} = \frac{3}{6} + \frac{2}{6} = \frac{5}{6}\) б) \(\frac{1}{3} + \frac{2}{7} = \frac{7}{21} + \frac{6}{21} = \frac{13}{21}\) в) \(\frac{2}{5} + \frac{1}{3} = \frac{6}{15} + \frac{5}{15} = \frac{11}{15}\) г) \(\frac{3}{7} + \frac{4}{9} = \frac{27}{63} + \frac{28}{63} = \frac{55}{63}\) д) \(\frac{5}{9} - \frac{1}{6} = \frac{10}{18} - \frac{3}{18} = \frac{7}{18}\) е) \(\frac{3}{4} - \frac{1}{3} = \frac{9}{12} - \frac{4}{12} = \frac{5}{12}\) ж) \(\frac{1}{6} + \frac{1}{3} = \frac{1}{6} + \frac{2}{6} = \frac{3}{6} = \frac{1}{2}\) з) \(\frac{9}{5} - \frac{7}{10} = \frac{18}{10} - \frac{7}{10} = \frac{11}{10} = 1\frac{1}{10}\) и) \(\frac{1}{2} - \frac{3}{8} = \frac{4}{8} - \frac{3}{8} = \frac{1}{8}\) к) \(\frac{7}{15} - \frac{3}{10} = \frac{14}{30} - \frac{9}{30} = \frac{5}{30} = \frac{1}{6}\) л) \(\frac{3}{8} + \frac{5}{12} = \frac{9}{24} + \frac{10}{24} = \frac{19}{24}\) м) \(\frac{5}{9} - \frac{1}{6} = \frac{10}{18} - \frac{3}{18} = \frac{7}{18}\) н) \(\frac{5}{11} + \frac{3}{5} = \frac{25}{55} + \frac{33}{55} = \frac{58}{55} = 1\frac{3}{55}\) о) \(\frac{17}{30} - \frac{3}{6} = \frac{17}{30} - \frac{15}{30} = \frac{2}{30} = \frac{1}{15}\) п) \(\frac{17}{35} - \frac{4}{15} = \frac{51}{105} - \frac{28}{105} = \frac{23}{105}\)
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