5.457 Уменьшив целую часть чисел 3\(\frac{4}{9}\), 9\(\frac{21}{22}\), \(\frac{4}{10}\) на единицу, запишите результат ты в виде неправильной дроби.

3 \(\frac{4}{9}\) - 1 = 2 \(\frac{4}{9}\) = \(\frac{2 \cdot 9 + 4}{9}\) = \(\frac{18 + 4}{9}\) = \(\frac{22}{9}\)

9 \(\frac{21}{22}\) - 1 = 8 \(\frac{21}{22}\) = \(\frac{8 \cdot 22 + 21}{22}\) = \(\frac{176 + 21}{22}\) = \(\frac{197}{22}\)

4 \(\frac{9}{10}\) - 1 = 3 \(\frac{9}{10}\) = \(\frac{3 \cdot 10 + 9}{10}\) = \(\frac{30 + 9}{10}\) = \(\frac{39}{10}\)

Ответ: \(\frac{22}{9}\), \(\frac{197}{22}\), \(\frac{39}{10}\)