Ответ:
а) \(\dfrac{3.5^2-2.5^2}{0.8\cdot0.6-0.6^2}=\dfrac{12.25-6.25}{0.48-0.36}=\dfrac{6}{0.12}=50\).
б) \(\dfrac{4(0.8^2-0.8\cdot1.7+1.7^2)}{1.6^3+3.4^3}=\dfrac{4(0.64-1.36+2.89)}{4.096+39.304}=\dfrac{8.68}{43.4}=0.2\).
Ответ: а) 50; б) 0,2.
а) \(\dfrac{3.5^2-2.5^2}{0.8\cdot0.6-0.6^2}=\dfrac{12.25-6.25}{0.48-0.36}=\dfrac{6}{0.12}=50\).
б) \(\dfrac{4(0.8^2-0.8\cdot1.7+1.7^2)}{1.6^3+3.4^3}=\dfrac{4(0.64-1.36+2.89)}{4.096+39.304}=\dfrac{8.68}{43.4}=0.2\).
Ответ: а) 50; б) 0,2.