Решение:
- \( 2 \frac{1}{4} : 1 \frac{2}{5} = \frac{9}{4} : \frac{7}{5} = \frac{9}{4} \cdot \frac{5}{7} = \frac{45}{28} = 1 \frac{17}{28} \)
- \( 7 \frac{1}{2} + 2 \frac{1}{4} = \frac{15}{2} + \frac{9}{4} = \frac{30+9}{4} = \frac{39}{4} \)
- \( \frac{39}{4} : \frac{1}{2} = \frac{39}{4} \cdot 2 = \frac{39}{2} = 19 \frac{1}{2} \)
- \( 19 \frac{1}{2} - 30 \frac{5}{6} = \frac{39}{2} - \frac{185}{6} = \frac{39 \cdot 3 - 185}{6} = \frac{117 - 185}{6} = \frac{-68}{6} = - \frac{34}{3} = -11 \frac{1}{3} \)
Ответ: а) \( 1 \frac{17}{28} \); б) \( -11 \frac{1}{3} \).