a) Вычислим ( \frac{2 \cdot 3^{20} - 5 \cdot 3^{19}}{9^9} = \frac{2 \cdot 3 \cdot 3^{19} - 5 \cdot 3^{19}}{(3^2)^9} = \frac{3^{19} (2 \cdot 3 - 5)}{3^{18}} = \frac{3^{19} (6 - 5)}{3^{18}} = \frac{3^{19} \cdot 1}{3^{18}} = 3^{19-18} = 3^1 = 3 \).
Ответ: 3