Решение:
\[ \frac{7}{10} + 2\frac{3}{5} = \frac{7}{10} + \frac{13}{5} = \frac{7}{10} + \frac{13 \times 2}{5 \times 2} = \frac{7}{10} + \frac{26}{10} = \frac{33}{10} \]
\[ 4\frac{2}{5} : \frac{33}{10} = \frac{22}{5} : \frac{33}{10} = \frac{22}{5} \times \frac{10}{33} \]
\[ \frac{22}{5} \times \frac{10}{33} = \frac{22}{33} \times \frac{10}{5} = \frac{2}{3} \times 2 = \frac{4}{3} = 1\frac{1}{3} \]
Ответ: \[ 1\frac{1}{3} \]