Ответ:

Для углов 90° ± α:

\[\sin(90°-\alpha)=\cos\alpha,\quad \sin(90°+\alpha)=\cos\alpha,\]

\[\cos(90°-\alpha)=\sin\alpha,\quad \cos(90°+\alpha)=-\sin\alpha,\]

\[\tan(90°-\alpha)=\frac{1}{\tan\alpha},\quad \tan(90°+\alpha)=-\frac{1}{\tan\alpha}.\]

Для углов 180° ± α:

\[\sin(180°-\alpha)=\sin\alpha,\quad \sin(180°+\alpha)=-\sin\alpha,\]

\[\cos(180°-\alpha)=-\cos\alpha,\quad \cos(180°+\alpha)=-\cos\alpha,\]

\[\tan(180°-\alpha)=-\tan\alpha,\quad \tan(180°+\alpha)=\tan\alpha.\]

Для углов 360° ± α:

\[\sin(360°-\alpha)=-\sin\alpha,\quad \sin(360°+\alpha)=\sin\alpha,\]

\[\cos(360°-\alpha)=\cos\alpha,\quad \cos(360°+\alpha)=\cos\alpha,\]

\[\tan(360°-\alpha)=-\tan\alpha,\quad \tan(360°+\alpha)=\tan\alpha.\]