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МатематикаВопрос:
B) \(\frac{3d+1}{2d+2}-1\):\(\frac{6d-6}{d+1}\);
Ответ:
Преобразуем выражение:
- $$\frac{3d+1}{2d+2}-1 = \frac{3d+1-2(d+1)}{2(d+1)} = \frac{3d+1-2d-2}{2(d+1)} = \frac{d-1}{2(d+1)}$$
Разделим первую дробь на вторую:
$$\frac{d-1}{2(d+1)}:\frac{6d-6}{d+1} = \frac{d-1}{2(d+1)} \cdot \frac{d+1}{6(d-1)} = \frac{1}{12}$$
Ответ: $$\frac{1}{12}$$
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