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МатематикаВопрос:
в) \(\frac{x-2y}{xy}+\frac{1}{x}\)\(\cdot\) \(\frac{x^2y^2}{x-y}\);
Ответ:
Преобразуем выражение:
- $$\frac{x-2y}{xy}+\frac{1}{x} = \frac{x-2y+y}{xy} = \frac{x-y}{xy}$$
Умножим первую дробь на вторую:
$$\frac{x-y}{xy} \cdot \frac{x^2y^2}{x-y} = xy$$
Ответ: xy
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