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МатематикаВопрос:
в) \(\frac{z-3}{z+3}\)\(\cdot\) \(z+\frac{z^2}{3-z}\);
Ответ:
Преобразуем выражение:
- $$z+\frac{z^2}{3-z} = \frac{z(3-z)+z^2}{3-z} = \frac{3z-z^2+z^2}{3-z} = \frac{3z}{3-z}$$
Умножим первую дробь на вторую:
$$\frac{z-3}{z+3} \cdot \frac{3z}{3-z} = -\frac{3z}{z+3}$$
Ответ: -$$\frac{3z}{z+3}$$
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