Решение:
\[ 15x - 17x + 3 = -2x + 3 \]
\[ 7 - 19 - 5x = -12 - 5x \]
\[ -2x + 3 \le -12 - 5x \]
\[ -2x + 5x \le -12 - 3 \]
\[ 3x \le -15 \]
\[ x \le \frac{-15}{3} \]
\[ x \le -5 \]
Ответ: x ≤ -5
x ≤ -5