Подставим $$u=-\frac{5}{6}$$ в выражение $$-u(2-u) - (2+u)^2$$:
$$-(-\frac{5}{6})(2-(-\frac{5}{6})) - (2+(-\frac{5}{6}))^2 = \frac{5}{6}(2+\frac{5}{6}) - (2-\frac{5}{6})^2 = \frac{5}{6}(\frac{12+5}{6}) - (\frac{12-5}{6})^2 = \frac{5}{6} \cdot \frac{17}{6} - (\frac{7}{6})^2 = \frac{85}{36} - \frac{49}{36} = \frac{36}{36} = 1$$
Ответ: 1