1) (12y-36)(0,5+2y) = 0; 2) 6(2x-1) + 3x =7x-4.

1) Решим уравнение: $$(12y - 36)(0,5 + 2y) = 0$$.

$$12y - 36 = 0$$ или $$0,5 + 2y = 0$$.

$$12y = 36$$

$$y = \frac{36}{12}$$

$$y = 3$$

$$2y = -0,5$$

$$y = \frac{-0,5}{2}$$

$$y = -0,25$$

2) Решим уравнение: $$6(2x - 1) + 3x = 7x - 4$$.

$$12x - 6 + 3x = 7x - 4$$

$$15x - 6 = 7x - 4$$

$$15x - 7x = -4 + 6$$

$$8x = 2$$

$$x = \frac{2}{8}$$

$$x = 0,25$$

Ответ: 1) $$y = 3$$ или $$y = -0,25$$, 2) $$x = 0,25$$