08. Вычислите: а) 18 · (1/9)² − 20 − 1/9; б) (1 5/8 + 3/12) · 1 5/48; в) (2 3/4 + 2 1/5) · 16.

а) \(18\cdot\left(\frac19\right)^2-20-\frac19=\frac29-20-\frac19=\frac19-20=-\frac{179}{9}\).

б) \(1\frac58+\frac3{12}=\frac{13}{8}+\frac14=\frac{15}{8}\). Тогда \(\frac{15}{8}\cdot1\frac5{48}=\frac{15}{8}\cdot\frac{53}{48}=\frac{265}{128}=2\frac9{128}\).

в) \(\left(2\frac34+2\frac15\right)\cdot16=\left(\frac{11}{4}+\frac{11}{5}\right)\cdot16=\frac{99}{20}\cdot16=\frac{396}{5}=79\frac15\).