\( \frac{19}{11} = \frac{19 × 10}{11 × 10} = \frac{190}{110} \)
\( \frac{17}{10} = \frac{17 × 11}{10 × 11} = \frac{187}{110} \)
\( \frac{190}{110} + \frac{187}{110} = \frac{377}{110} \)
\( \frac{377}{110} \times \frac{11}{5} = \frac{377}{10 × 11} \times \frac{11}{5} = \frac{377}{10 \times 5} = \frac{377}{50} \)
\( \frac{377}{50} = 7 \frac{27}{50} \)
Ответ: \( 7\frac{27}{50} \)