Ответ:
Решение:
- \( \cos 120^{\circ} = \cos (180^{\circ} - 60^{\circ}) = -\cos 60^{\circ} = -\frac{1}{2} \).
- \( \sin (-150^{\circ}) = -\sin 150^{\circ} = -\sin (180^{\circ} - 30^{\circ}) = -\sin 30^{\circ} = -\frac{1}{2} \).
- \( \text{tg} (-225^{\circ}) = -\text{tg} 225^{\circ} = -\text{tg} (180^{\circ} + 45^{\circ}) = -\text{tg} 45^{\circ} = -1 \).
- \( \cos (-225^{\circ}) = \cos 225^{\circ} = \cos (180^{\circ} + 45^{\circ}) = -\cos 45^{\circ} = -\frac{\sqrt{2}}{2} \).
- \( \cos \frac{7\pi}{6} = \cos (\pi + \frac{\pi}{6}) = -\cos \frac{\pi}{6} = -\frac{\sqrt{3}}{2} \).
- \( \sin \frac{4\pi}{3} = \sin (\pi + \frac{\pi}{3}) = -\sin \frac{\pi}{3} = -\frac{\sqrt{3}}{2} \).
Ответ: а) \( -\frac{1}{2} \); б) \( -\frac{1}{2} \); в) \( -1 \); г) \( -\frac{\sqrt{2}}{2} \); д) \( -\frac{\sqrt{3}}{2} \); е) \( -\frac{\sqrt{3}}{2} \).
