Преобразуем углы:
\(\frac{21π}{4}\) = 5π + \(\frac{π}{4}\)
\(\frac{11π}{3}\) = 3π + \(\frac{2π}{3}\)
ctga(5π + \(\frac{π}{4}\)) = ctg(\(\frac{π}{4}\)) = 1
cos(3π + \(\frac{2π}{3}\)) = cos(\(\frac{2π}{3}\)) = -\(\frac{1}{2}\)
ctga(5π + \(\frac{π}{4}\)) * cos(3π + \(\frac{2π}{3}\)) = 1 * -\(\frac{1}{2}\) = -\(\frac{1}{2}\)
Ответ: -\(\frac{1}{2}\)