\(\frac{x-1}{3} - 3\left(2x - \frac{5-2(x-1)}{4}\right) > x + 2\frac{3}{4}\)
\(2x - \frac{5-2(x-1)}{4} = 2x - \frac{5-2x+2}{4} = 2x - \frac{7-2x}{4} = \frac{8x - 7 + 2x}{4} = \frac{10x - 7}{4}\)
\(\frac{x-1}{3} - 3\left(\frac{10x - 7}{4}\right) > x + \frac{11}{4}\)
\(4(x-1) - 9(10x - 7) > 12x + 33\)
\(4x - 4 - 90x + 63 > 12x + 33\)
\(-86x + 59 > 12x + 33\)
\(-86x - 12x > 33 - 59\)
\(-98x > -26\)
\(x < \frac{-26}{-98}\)
\(x < \frac{13}{49}\)
Ответ: \(x < \frac{13}{49}\)