B) \(\frac{2m+1}{4}+3=\frac{m}{6}\);

B) Решим уравнение: $$\frac{2m+1}{4}+3=\frac{m}{6}$$

Приведем дроби к общему знаменателю 12:

$$\frac{3(2m+1)}{12}+\frac{36}{12}=\frac{2m}{12}$$

$$\frac{6m+3}{12}+\frac{36}{12}=\frac{2m}{12}$$

$$\frac{6m+3+36}{12}=\frac{2m}{12}$$

$$\frac{6m+39}{12}=\frac{2m}{12}$$

$$6m+39 = 2m$$

$$6m-2m = -39$$

$$4m = -39$$

$$m = -\frac{39}{4}$$

$$m = -9.75$$

Ответ: $$m = -9.75$$