Разбираемся:
\(\frac{a(9a^2-64)}{(\frac{3a+8}{3a} - \frac{3a-8}{3a})} = \frac{a(9a^2-64)}{\frac{3a+8 - (3a-8)}{3a}} = \frac{a(9a^2-64)}{\frac{16}{3a}} = \frac{3a^2(9a^2-64)}{16}\)
\(\frac{3(30.6)^2(9(30.6)^2-64)}{16}\)
Ответ: \(\frac{3(30.6)^2(9(30.6)^2-64)}{16}\)