Решение:
\[ 2\frac{1}{3} = \frac{2 \times 3 + 1}{3} = \frac{6 + 1}{3} = \frac{7}{3} \]
\[ \frac{7}{3} \times 5 = \frac{7}{3} \times \frac{5}{1} = \frac{7 \times 5}{3 \times 1} = \frac{35}{3} \]
\[ \frac{35}{3} = 35 \div 3 = 11 \text{ (остаток } 2) = 11\frac{2}{3} \]
Ответ: 11⅒