Решение:
\[ 2\frac{1}{3} = \frac{2 \times 3 + 1}{3} = \frac{6 + 1}{3} = \frac{7}{3} \]
\[ \frac{7}{3} \times 4 = \frac{7}{3} \times \frac{4}{1} = \frac{7 \times 4}{3 \times 1} = \frac{28}{3} \]
\[ \frac{28}{3} = 28 \div 3 = 9 \text{ (остаток } 1) = 9\frac{1}{3} \]
Ответ: 9⅓