Решение:
\[ 2\frac{1}{9} = \frac{2 \times 9 + 1}{9} = \frac{18 + 1}{9} = \frac{19}{9} \]
\[ \frac{19}{9} \times 2 = \frac{19}{9} \times \frac{2}{1} = \frac{19 \times 2}{9 \times 1} = \frac{38}{9} \]
\[ \frac{38}{9} = 38 \div 9 = 4 \text{ (остаток } 2) = 4\frac{2}{9} \]
Ответ: 4&frac29;