Решение:
\[ 1\frac{1}{3} = \frac{1 \times 3 + 1}{3} = \frac{3 + 1}{3} = \frac{4}{3} \]
\[ 8 \times \frac{4}{3} = \frac{8}{1} \times \frac{4}{3} = \frac{8 \times 4}{1 \times 3} = \frac{32}{3} \]
\[ \frac{32}{3} = 32 \div 3 = 10 \text{ (остаток } 2) = 10\frac{2}{3} \]
Ответ: 10⅔