Ответ:
\(\sin(\alpha-3\pi)=-\sin\alpha\), \(\cos(\alpha-\frac\pi2)=\sin\alpha\), \(\sin(\alpha-\pi)=-\sin\alpha\).
\[\frac{2(-\sin\alpha)-\sin\alpha}{5(-\sin\alpha)}=\frac{-3\sin\alpha}{-5\sin\alpha}=\frac35.\]
Ответ: \(\frac35\).
\(\sin(\alpha-3\pi)=-\sin\alpha\), \(\cos(\alpha-\frac\pi2)=\sin\alpha\), \(\sin(\alpha-\pi)=-\sin\alpha\).
\[\frac{2(-\sin\alpha)-\sin\alpha}{5(-\sin\alpha)}=\frac{-3\sin\alpha}{-5\sin\alpha}=\frac35.\]
Ответ: \(\frac35\).